37, 解数独
大约 4 分钟
一、题目描述
编写一个程序,通过填充空格来解决数独问题。
数独的解法需遵循如下规则:
- 数字
1-9
在每一行只能出现一次。 - 数字
1-9
在每一列只能出现一次。 - 数字
1-9
在每一个以粗实线分隔的3x3
宫内只能出现一次。(请参考示例图)
数独部分空格内已填入了数字,空白格用'.'
表示。
示例 1
输入: board =
[["5","3",".",".","7",".",".",".","."]
,["6",".",".","1","9","5",".",".","."]
,[".","9","8",".",".",".",".","6","."]
,["8",".",".",".","6",".",".",".","3"]
,["4",".",".","8",".","3",".",".","1"]
,["7",".",".",".","2",".",".",".","6"]
,[".","6",".",".",".",".","2","8","."]
,[".",".",".","4","1","9",".",".","5"]
,[".",".",".",".","8",".",".","7","9"]]
输出:
[["5","3","4","6","7","8","9","1","2"]
,["6","7","2","1","9","5","3","4","8"]
,["1","9","8","3","4","2","5","6","7"]
,["8","5","9","7","6","1","4","2","3"]
,["4","2","6","8","5","3","7","9","1"]
,["7","1","3","9","2","4","8","5","6"]
,["9","6","1","5","3","7","2","8","4"]
,["2","8","7","4","1","9","6","3","5"]
,["3","4","5","2","8","6","1","7","9"]]
解释: 输入的数独如上图所示,唯一有效的解决方案如下所示:
提示
board.length == 9
board[i].length == 9
board[i][j]
是一位数字或者'.'
- 题目数据保证输入数独仅有一个解
相关主题
- 数组
- 哈希表
- 回溯
- 矩阵
二、题解
方法 1: 回溯
pub fn solve_sudoku(board: &mut Vec<Vec<char>>) {
let mut row = vec![vec![false; 9]; 9];
let mut col = vec![vec![false; 9]; 9];
let mut sub_boxes = vec![vec![vec![false; 3]; 3]; 9];
let mut spaces = vec![];
let mut valid = false;
for i in 0..9 {
for j in 0..9 {
if board[i][j] == '.' {
spaces.push((i, j));
} else {
let idx = (board[i][j] as u8 - b'1') as usize;
(row[i][idx], col[j][idx], sub_boxes[idx][i / 3][j / 3]) = (true, true, true);
}
}
}
const DFS: fn(
&mut Vec<Vec<char>>,
usize,
&Vec<(usize, usize)>,
&mut Vec<Vec<bool>>,
&mut Vec<Vec<bool>>,
&mut Vec<Vec<Vec<bool>>>,
&mut bool,
) = |board, pos, spaces, row, col, sub_boxes, valid| {
if pos == spaces.len() {
*valid = true;
return;
}
let (i, j) = spaces[pos];
for idx in 0..9 {
if *valid {
break;
}
if !row[i][idx] && !col[j][idx] && !sub_boxes[idx][i / 3][j / 3] {
(row[i][idx], col[j][idx], sub_boxes[idx][i / 3][j / 3]) = (true, true, true);
board[i][j] = (b'1' + (idx as u8)) as char;
DFS(board, pos + 1, spaces, row, col, sub_boxes, valid);
(row[i][idx], col[j][idx], sub_boxes[idx][i / 3][j / 3]) = (false, false, false);
}
}
};
DFS(board, 0, &spaces, &mut row, &mut col, &mut sub_boxes, &mut valid);
}
public class Solution {
List<int[]> spaces;
boolean valid;
@FunctionalInterface
interface QuintConsumer<A, B, C, D, E> {
void accept(A a, B b, C c, D d, E e);
}
@FunctionalInterface
interface SeptConsumer<A, B, C, D, E, F, G> {
void accept(A a, B b, C c, D d, E e, F f, G g);
}
QuintConsumer<char[][], Integer, boolean[][], boolean[][], boolean[][][]> dfs1 =
(board, pos, row, col, subBoxes) -> {
if (pos == this.spaces.size()) {
this.valid = true;
return;
}
int i = spaces.get(pos)[0];
int j = spaces.get(pos)[1];
for (int idx = 0; idx < 9 && !this.valid; idx++) {
if (!row[i][idx] && !col[j][idx] && !subBoxes[i / 3][j / 3][idx]) {
board[i][j] = (char) (idx + '1');
this.flip1.accept(row, col, subBoxes, i, j, idx, true);
this.dfs1.accept(board, pos + 1, row, col, subBoxes);
this.flip1.accept(row, col, subBoxes, i, j, idx, false);
}
}
};
SeptConsumer<boolean[][], boolean[][], boolean[][][], Integer, Integer, Integer, Boolean> flip1 =
(row, col, subBoxes, i, j, idx, val) -> {
row[i][idx] = val;
col[j][idx] = val;
subBoxes[i / 3][j / 3][idx] = val;
};
public void solveSudoku(char[][] board) {
boolean[][] row = new boolean[9][9];
boolean[][] col = new boolean[9][9];
boolean[][][] subBoxes = new boolean[3][3][9];
this.spaces = new ArrayList<>();
for (int i = 0; i < 9; i++) {
for (int j = 0; j < 9; j++) {
if (board[i][j] == '.') {
this.spaces.add(new int[]{i, j});
} else {
int idx = board[i][j] - '1';
this.flip1.accept(row, col, subBoxes, i, j, idx, true);
}
}
}
this.dfs1.accept(board, 0, row, col, subBoxes);
}
}
方法 2: 位运算优化
pub fn solve_sudoku(board: &mut Vec<Vec<char>>) {
let mut row = vec![0; 9];
let mut col = vec![0; 9];
let mut sub_boxes = vec![vec![0; 3]; 3];
let mut spaces = vec![];
let mut valid = false;
for i in 0..9 {
for j in 0..9 {
if board[i][j] == '.' {
spaces.push((i, j));
} else {
let digit = (board[i][j] as u8 - b'1') as usize;
row[i] ^= 1 << digit;
col[j] ^= 1 << digit;
sub_boxes[i / 3][j / 3] ^= 1 << digit;
}
}
}
const DFS: fn(
&mut Vec<Vec<char>>,
usize,
&Vec<(usize, usize)>,
&mut Vec<i32>,
&mut Vec<i32>,
&mut Vec<Vec<i32>>,
&mut bool,
) = |board, pos, spaces, row, col, sub_boxes, valid| {
if pos == spaces.len() {
*valid = true;
return;
}
let (i, j) = spaces[pos];
let mut mask = !(row[i] | col[j] | sub_boxes[i / 3][j / 3]) & 0x1ff;
while mask != 0 && !*valid {
let digit = (mask & (-mask)).trailing_zeros();
row[i] ^= 1 << digit;
col[j] ^= 1 << digit;
sub_boxes[i / 3][j / 3] ^= 1 << digit;
board[i][j] = (digit as u8 + b'1') as char;
DFS(board, pos + 1, spaces, row, col, sub_boxes, valid);
row[i] ^= 1 << digit;
col[j] ^= 1 << digit;
sub_boxes[i / 3][j / 3] ^= 1 << digit;
mask &= mask - 1;
}
};
DFS(board, 0, &spaces, &mut row, &mut col, &mut sub_boxes, &mut valid);
}
public class Solution {
List<int[]> spaces;
boolean valid;
@FunctionalInterface
interface QuintConsumer<A, B, C, D, E> {
void accept(A a, B b, C c, D d, E e);
}
@FunctionalInterface
interface SexConsumer<A, B, C, D, E, F> {
void accept(A a, B b, C c, D d, E e, F f);
}
QuintConsumer<char[][], Integer, int[], int[], int[][]> dfs2 =
(board, pos, row, col, subBoxes) -> {
if (pos == this.spaces.size()) {
this.valid = true;
return;
}
int i = this.spaces.get(pos)[0];
int j = this.spaces.get(pos)[1];
int mask = ~(row[i] | col[j] | subBoxes[i / 3][j / 3]) & 0x1ff;
for (; mask != 0 && !this.valid; mask &= mask - 1) {
int digit = Integer.bitCount((mask & (-mask)) - 1);
board[i][j] = (char) (digit + '1');
this.flip2.accept(row, col, subBoxes, i, j, digit);
this.dfs2.accept(board, pos + 1, row, col, subBoxes);
this.flip2.accept(row, col, subBoxes, i, j, digit);
}
};
SexConsumer<int[], int[], int[][], Integer, Integer, Integer> flip2 =
(row, col, subBoxes, i, j, digit) -> {
row[i] ^= 1 << digit;
col[j] ^= 1 << digit;
subBoxes[i / 3][j / 3] ^= 1 << digit;
};
public void solveSudoku(char[][] board) {
int[] row = new int[9];
int[] col = new int[9];
int[][] subBoxes = new int[3][3];
this.spaces = new ArrayList<>();
for (int i = 0; i < 9; i++) {
for (int j = 0; j < 9; j++) {
if (board[i][j] == '.') {
this.spaces.add(new int[]{i, j});
} else {
int digit = board[i][j] - '1';
this.flip2.accept(row, col, subBoxes, i, j, digit);
}
}
}
this.dfs2.accept(board, 0, row, col, subBoxes);
}
}